Which of the following reactions obeys the Law of Conservation of Atoms?
H20 - H2 + O2
CuSO4 + Zn - ZnCl2 + Cu
Zn + HCI – ZnCl2 + H2
PbCl2 + Al - AlCl3 + Pb -
Zn + 2HCI - H2 + ZnCl2

there are 1 atom of Zn, 2 atoms of H and 2 atoms of Cl

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2