A chemical reaction was used to produce 2.54 moles of copper(II) bicarbonate, Cu(HCO3)2. What mass of copper(II) bicarbonate was produced?

The answer to your question is 471.2 g

Explanation:

Data

moles of Cu(HCO₃)₂ = 2.54

mass of Cu(HCO₃)₂ = ?

Process

1.- Calculate the molar mass of Copper (II) bicarbonate

Cu(HCO₃)₂ = (1 x 63.5) + (2 x 1) + (2 x 12) + (6 x 16)

                  = 63.5 + 2 + 24 + 96

                  = 185.5 g

2.- Use proportions and cross multiplication to find the mass

                     185.5 g of Cu(HCO₃)₂ 1 mol

                         x                               2.54 mol

                                   x = (2.54 x 185.5) / 1

                                   x = 471.2 g