Among the many complex ions of cobalt are Co(NH3)63+(aq) + 3 en(aq) ⇌ Co(en)33+(aq) + 6 NH3(aq) where "en" stands for ethylenediamine, H2NCH2CH2NH2. Six Co―N bonds are broken, and six Co―N bonds are formed in this reaction, so ΔH o rxn ≈ 0; yet K > 1. What are the signs of ΔS o and ΔG o ? ΔS o < 0 ΔS o = 0 ΔS o > 0 ΔG o < 0 ΔG o = 0 ΔG o > 0 What drives the reaction? Free energy is positive. Enthapy is ≈ 0. a decrease in entropy an increase in entropy