The standard enthalpy change for the combustion of 1 mole of propane is –2043.0 kJ. C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g) Calculate ΔfH° for propane based on the following standard molar enthalpies of formation. molecule ΔfH° (kJ/mol-rxn) CO2(g) –393.5 H2O(g) –241.8'

 -104.7 kJ

Explanation:

The chemical equation for the combustion of propane follows:

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

The enthalpy of formation of is -104.7 kJ/mol

answer; i believe the correct answer is (c) /// is a homogeneous mixture of gaseous substance nitrogen,oxygen and smaller amounts of other substancesmixtures can be either ( homogeneous or heterogeneous)plz check first good luck

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .