A balloon has a volume of 2.5 L and contains 0.100 moles of Helium. Another balloon has
a volume of 5.0 L. They are at the same temperature and pressure. How many moles of
gas does the second balloon contain?

n₂ = 0.2 mol

Explanation:

Given data:

Volume of 1st balloon = 2.5 L

Moles of He in 1st balloon = 0.100 mol

Volume of second balloon = 5.0 L

Moles in second balloon = ?

Solution:

According to the Avogadro law,

Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.

Mathematical expression:

V₁/n₁  =  V₂/n₂

V₁ = Volume of 1st balloon

n₁  =  Moles of He in 1st balloon

V₂ = Volume of second balloon

n₂ = Moles in second balloon

Now we will put the values.

2.5 L / 0.100 mol = 5 L /n₂

n₂ = 5 L× 0.100 mol  /2.5 L

n₂ = 0.5 mol /2.5

n₂ = 0.2 mol

14 days is the half-life of phosphorus-32

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