Calculate the pH of the solution after the addition of the following amounts of 0.0656 M HNO3 to a 70.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04.

a) 0.00 mL of HNO3; Ph=

b) 9.06 mL of HNO3; Ph=

c) Volume of HNO3 equal to half the equivalence point volume; Ph=

d) 77.0 mL of HNO3; Ph=

e) Volume of HNO3 equal to the equivalence point; Ph=

f) 83.8 mL of HNO3; Ph=