What is the molarity of a solution that contains 1.2 moles of calcium carbonate (CaCO3) in 1.22 liters of solution? Round to the nearest hundreth.

The molarity of this CaCO3 solution is 0.98 M

Explanation:

Step 1: Data given

Number of moles calcium carbonate (CaCO3) = 1.2 moles

Volume of the solution = 1.22 L

Step 2: Calculate the molarity of this CaCO3 solution

Molarity = moles / volume

Molarity CaCO3 solution = moles CaCO3 / volume of the solution

Molarity CaCO3 solution = 1.2 moles CaCO3 / 1.22 L

Molarity CaCO3 solution = 0.98 mol/L = 0.98 M

The molarity of this CaCO3 solution is 0.98 M

c. orbital shape i hope this is correct