A chunk of aluminum at 91.4°C was added to 200.0 g of water at 15.5°C. The specific heat of aluminum is 0.897 J/g°C, and the specific heat of water is 4.18 J/g°C. When the temperature stabilized, the temperature of the mixture was 18.9°C. Assuming no heat was lost to the surroundings, what was the mass of aluminum added?

A. 243 g
B. 34.7 g
C. 41.7 g
D. 43.7 g

Explanation:

Hello,

In this case, since the heat lost by the aluminium is gained by the water, the following equality is achieved:

Which in terms of masses, heat capacities and temperatures is:

Thus, by solving for the mass of aluminium, we obtain:

Best regards.

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph