Balance the following skeleton reaction in acidic solution (if the coefficient is 1, put 1; if the coefficient is 0, put 0) and identify the oxidizing and reducing agents. For the oxidizing and reducing agent, enter numbers and +/- directly for superscripts and subscripts. (eg. enter HCO3- for HCO3-, Cu2+ for Cu2+) CrO42- (aq) + N2O (g) Cr3+ (aq) + NO (g) 2 CrO42–(aq) + 3 N2O(g) + 10 H+(aq) + 0 H2O(l) 2 Cr3+(aq) + 6 NO(g) + 0 H+(aq) + 5 H2O(l) (acidic) Oxidizing agent: CrO42- Reducing agent: N2O

2 CrO42- + 3N2O + 10 H+ > 2Cr3+ + 6NO + 5H2O

Explanation:

2 CrO42- + 3N2O + 10 H+ > 2Cr3+ + 6NO + 5H2O

Oxidizing agent: > CrO42-

Reducing agent: > N2O

explanation:

in CrO4-2 oxdiation state of Cr = +6

in Cr+3 oxidation state = +3

+6 oxidation state changed from +3 it is reduction .

so CrO4-2 is oxidizing agent

atomatically

N2O should be reducing agent

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.