A sample of O2 occupies 75 L at 1 atm. If the volume of the
sample doubles, what is the new pressure of 02?

0.5 atm

Explanation:

O2 is the chemical formula for molecular oxygen.

Given that,

Original pressure of O2 (P1) = 1 atm

Original volume of oxygen O2 (V1) = 75L

New pressure of O2 (P2) = ?

New volume of O2 (V2) = 2V1

i.e (2 x 75L)

= 150L

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

1 atm x 75L = P2 x 150L

75 atm•L = 150L•P2

Divide both sides by 150L to get P2

75 atm•L / 150L = 150L•P2/150L

0.5 atm = P2

Thus, the new pressure of 02 is 0.5 atmosphere

idk i’m struggling too