If the volume of a gas at 200.0 kPa is 25.5 L. what is the new volume of the gas at 11.2 atm of pressure?

2.22 litres

Explanation:

Given that,

Original pressure of gas (P1) = 200.0 kPa

[Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere

If 101.325 kPa = 1 atm

200.0 kPa = 200.0/101.325

= 1.9738 atm]

Original volume of oxygen O2 (V1) = 25.5L

New pressure of gas (P2) = 11.2 atm

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

0.9738 atm x 25.5L = 11.2 atm x V2

24.8319 atm•L = 11.2 atm•V2

Divide both sides by 11.2 atm to get V2

24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm

2.217 L = V2

[Round 2.217L to the nearest hundredth as 2.22L]

Thus, the new volume of the gas at 11.2 atm of pressure is 2.22 litres

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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