The reaction 2 H2 + O2 → 2 H2O produces water. When 10.0 g H2 reacts with 64.0 g O2 in a large tank, the final mixture in the tank after the reaction finishes will contain 1. H2 and H2O . 2. O2 . 3. O2 and H2O . 4. O2 and H2 . 5. H2, O2, and H2O . 6. H2O . 7. H2 .

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole