Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide: 2NaI(aq) +Cl2(g) → I2(s) +2NaCl(aq) How many grams of iodide, NaI, must be used to produce 55.6 g of iodine, I2?

65.7 gram

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of are produced by = 2 moles of

Thus 0.219 moles of will be produced by = of

Mass of

Thus 65.7 g of NaI, must be used to produce 55.6 g of iodine

it is a solid

explanation:

the answer is c

tell me if wrong