In pure water, some of the molecules ionize according to the equation H2O→H+ + OH−. The extent of the ionization increases with temperature. A student heats pure water and records the measured pH at 50°C as 6.6. Based on this information, what mathematical relationships gives the pOH pOH of pure water at 50°C?

Answer : The mathematical relationships gives the pOH of pure water at is,

Explanation :

As we are given that the pH at is, 6.6.

Now we have to determine the mathematical relationships gives the pOH of pure water at .

As we know that:

The ionization of water is:

The expression for dissociation constant for water is:

taking logarithm on both side, we get:

Taking negative sign on both side, we get:

As we know that the value of is 14 at 25-50°C.

So,

or,

Therefore, the mathematical relationships gives the pOH of pure water at is,

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.