Dalton's Law of Partial pressure: The total pressure of a gas mixture is the sum of the partial pressures of each gas . Therefore if I have a gas chamber with 3.1 atm of Xe and 0.8 atm of N2 and no H2,.. What is the pressure in the chamber.

The total pressure of this gas mixture in the chamber is 3.9 atm

Explanation:

Step 1: Data given

Partial pressure of Xe = 3.1 atm

Partial pressure of N2 = 0.8 atm

Partial pressure of H2= 0 atm

Dalton's law says: Total pressure of a gas mixture = sum of partial pressure of gasses

Step 2: Calculate the total pressure of a gas mixture

Dalton's law says: Total pressure of a gas mixture = sum of partial pressure of gasses

Total pressure of the gas mixture = Partial pressure of Xe + Partial pressure of N2 + partial pressure of H2

Total pressure of the gas mixture = 3.1 atm + 0.8 atm + 0 atm

Total pressure of the gas mixture =  3.9 atm

The total pressure of this gas mixture in the chamber is 3.9 atm

you need to have a picture of the atom that way we can answer it

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied