When 0.800 grams of NaOH is dissolved in 100.0 grams of water, the temperature of the solution increases from 25.00 oC to 27.06 oC. The amount of heat absorbed by the water is J. (The specific heat of water is 4.18 J/g - oC.)

The amount of heat absorbed by the water is Q = 861.08 Joule

Explanation:

Mass of water = 100 gm

Temperature change ΔT = 27.06 - 25 = 2.06 °c

We know that heat absorbed by the water is given by

Q = m C ΔT

Put all the values in above equation we get

Q = 100 × 4.18 × 2.06

Q = 861.08 Joule

Therefore the amount of heat absorbed by the water is Q = 861.08 Joule

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: