For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) SO2(g)+NO2(g)↽−−⇀SO3(g)+NO(g) the equilibrium constant at a certain temperature is 2.70 . 2.70. At this temperature, calculate the number of moles of NO 2 ( g ) NO2(g) that must be added to 2.99 mol SO 2 ( g ) 2.99 mol SO2(g) in order to form 1.30 mol SO 3 ( g ) 1.30 mol SO3(g) at equilibrium.

Answer : The number of moles of added must be, 0.37 mol

Explanation :

The given chemical reaction is:

Initial mol.     2.99           x                 0           0

At eqm.      (2.99-1.30)  (x-1.30)         1.30       1.30

                      = 1.69

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

x  = 1.67 mol

The moles of added = (x-1.30) = (1.67-1.30) = 0.37 mol

58750.08068 is the answer i think

points

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