Diiodine pentoxide (I2O5) is used in respirators to remove carbon monoxide (CO) from air according to the chemical equation: I2O5 (s) + 5 CO (g) --> I2 (s) + 5 CO2 (g) What mass of carbon monoxide could be removed from air by a respirator that contains 15.9 g of diiodine pentoxide? The molar mass of I2O5 is 333.8 g / mol.

mass of that can be removed from air=6.7gram

Explanation:

when you get this type of question first write their balance equation.

First write the balance chemical reaction:

given mass of diiodine pentaoxide=15.9gram

molar mass of diiodine pentaoxide=333.8g/mol

mole of diiodine pentaoxide =15.9/333.8mol

mole of diiodine pentaoxide=0.0476mol

from the above balance equation it is clear that;

1 mole diiodine pentaoxide remove 5 mole of CO from air

0.0476 mole of diiodine pentaoxide will remove of CO from air

mole of CO that can be removed=0.238mol

mass of that can be removed from air=6.664gram

mass of that can be removed from air=6.7gram

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

the volume increases