The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6 542 kJIf 8.700 g C6H6is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘C, what is the final temperature of the water?

Answer : The final temperature of the water is,

Explanation :

First we have to calculate the moles of benzene.

Mass of = 8.700 g

Molar mass of = 78 g/mol

Now we have to calculate the heat produced by the reaction.

As, 2 moles of benzene burns to give heat = 6542 kJ

So, 0.112 moles of benzene burns to give heat =

Now we have to calculate the final temperature of the water.

where,

q = heat produced = 366.4 kJ = 366400 J

m = mass of water = 5691 g

c = specific heat capacity of water =

= initial temperature =

= final temperature = ?

Now put all the given values in the above formula, we get:

Thus, the final temperature of the water is,