To determine the purity of a sample of Na2HPO4, a 2.469-g sample is dissolved and diluted to volume in a 100-mL volumetric flask. Analysis of the resulting solution gives an absorbance of 0.135. What is the purity of the Na2HPO4

Question: The question is incomplete. below is the calibrated data of the question and the answer.

ppm             Absorbance

2130           0.048

4260           0.110

6400           0.173

8530            0.230

% purity = 95.32

Explanation:

NOW MOLAR MASS OF Na2HPO4 =141.96

ATOMIC MASS OF PHOSPOROUS=30.974

141.96/30.974 =4.583 g

If  4.583g of  Na2HPO4 is added in 1000 ml volumetric flask and make the volume to 1L with water, you will get 1000 ppm P solution

Therefore, 2.469g in 100 mL =5387.300 PPM  

Calculating the percentage error, we have

%ERROR=(5387.300-5146.118)/5146.118 *100

               =4.68

SO %PURITY = 100-4.68 =95.32

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

the correct answer would be d. hope this !