Magnesium metal burns in the presence of oxygen gas to produce solid magnesium oxide. You are given 4.00 grams of magnesium and an excess of oxygen gas in a tank. How many grams of magnesium oxide can be produced?

We can produce 6.63 grams of Magnesium oxide

Explanation:

Step 1: Data given

Mass of magnesium = 4.00 grams

Molar mass of Magnesium = 24.305 g/mol

O2 is in excess

Molar mass of Magnesium oxide = 40.3044  g/mol

Step 2: The balanced equation

2Mg + O2 → 2MgO

For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide

Step 3: Calculate moles magnesium

Moles Mg = 4.00 grams / 24.305 g/mol

Moles Mg = 0.1646 moles

Step 4: Calculate moles Magnesiumoxide

For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide

For 0.1646 moles Mg we'll have 0.1646 moles MgO

Step 5: Calculate mass magnesium oxide

Mass MgO = Moles MgO * molar mass MgO

Mass MgO = 0.1646 moles* 40.3044 g/mol

Mass MgO = 6.63 grams

We can produce 6.63 grams of Magnesium oxide

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l