What is the molarity of an 85.0-mL ethanol (C2H5OH) solution

containing 1.77 g of ethanol?

The molarity of an 85.0-mL ethanol (C2H5OH) solution containing 1.77 g of ethanol is 0.45M

MOLARITY:

Learn more about molarity: link

The molarity of the solution is 0,45 M.

Explanation:

We know that molarity is a concentration measure that expresses moles of solute per liter of solution (1000ml). First we proceed to calculate the mass of 1 mole of compound from the atomic weights of the elements of the periodic table and then we calculate the molarity by a simple rule of three:

Weight 1 mol C2H5OH= (Weight C)x2 + (Weight H)x6 + Weight 0

Weight 1 mol C2H5OH=12 g x 2 + 1g x 6 + 16 g= 46 g/mol

46 g ---1 mol ethanol

1,77gx= (1,77g x  1 mol ethanol)/46 g= 0,038 mol ethanol

85 ml solution0,038 mol ethanol

1000ml solution---x= (1000ml solution x0,038 mol ethanol)/85 ml solution

x=0,45 M---> The solution is 0,45 M

може ли да зареждате повече информация, моля