A sample of SO2 gas has a volume of 1.16 L at a temperature of 23°C. At what temperature will the gas have a volume of 1.25 L?

46 degrees C

Explanation:

We use Charles' Law: , where V is the volume and T is the temperature in Kelvin.

Here, V_1 = 1.16 L and T_1 = 23 + 273 = 296 K. Also, V_2 = 1.25 L. Plugging these into the equation, we have:

Cross-multiplying, we have:

1.16 = 1.25 * 296 = 370  ⇒   = 370/1.16 ≈ 319 K

We want to convert this back to Celsius, so we just subtract 273 from 319:

319 - 273 = 46 degrees Celsius.

Hope this helps!

let that person have a turn to speak : )