2C2H6 + 7O2 > 4CO2 + 6H2O

In the combustion of ethane, how many
moles of CO2 can be produced from 3.00
mole of C2H6?

A: 3
B: 4
C: 6
D: 8

Option C) 6

Explanation:

2C2H6(g) + 7O2(g) ---> 4CO2(g) + 6H2O(g)

The equation above shows the combustion of ethane, C2H6 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O.

The mole ratio on combustion are as follows:

2 mole of C2H6 produce 4 mole of CO2

3 mole of C2H6 produce Z mole of CO2

To get the value of Z, cross multiply

Z x 2 mole = 3 mole x 4 mole

2Z = 12

Divide both sides by 2

2Z/2 = 12/2

Z = 6 moles

Thus, in the combustion of ethane, 6 moles of CO2 can be produced from 3.00 mole of C2H6

bcde is the incorrect answer it is a