5/10
5.00 moles of an ideal gas X was found to occupy a volume of
62.0 L at a pressure of 250. KPa and at a temperature of 100
*C. What is the value of the gas constant in ?
mol:K
mol-K (3 sig fias)
Enter the answer
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0.082 atm L k^-1 mole^-1

Explanation:

Given that:

Volume of gas (V) = 62.0 L

Temperature of gas (T) = 100°C

Convert 100°C to Kelvin by adding 273

(100°C + 273 = 373K)

Pressure of gas (P) = 250 kPa

[Convert pressure in kilopascal to atmospheres

101.325 kPa = 1 atm

250 kPa = 250/101.325 = 2.467 atm]

Number of moles (n) = 5.00 moles

Gas constant (R) = ?

To get the gas constant, apply the formula for ideal gas equation

pV = nRT

2.467 atm x 62.0L = 5.00 moles x R x 373K

152.954 atm•L = 1865 K•mole x R

To get the value of R, divide both sides by 1865 K•mole

152.954 atm•L / 1865 K•mole = 1865 K•mole•R / 1865 K•mole

0.082 atm•L•K^-1•mole^-1 = R

Thus, the value of gas constant is 0.082 atm L k^-1 mole^-1

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

idk what is it? is this a question that you know the answer or u dont