How many grams of oxygen are needed to complete the combustion of 8 g of methane, CH4

32 grams

Explanation:

So 1 mole of methane requires 2 moles of oxygen for complete combustion. So 16 g of Methane requires 64 g of oxygen for the complete combustion.

So 8 g of Methane requires = 8x64/16=32 g of oxygen.

the millers tale is the answer.

its first and third is your answer i did the qustion the fourth isnt right