If the pOH of vinegar is 9.45, what is its OH

[OH⁻] = 3.55×10⁻¹⁰M

Explanation:

Given data:

pOH of vinegar = 9.45

[OH]  = ?

Solution:

Formula:

pOH = -log[OH⁻]

Now we will put the value of pOH.

9.45 = -log[OH⁻]

[OH⁻] = 10∧-pOH

[OH⁻] = 10⁻⁹°⁴⁵

[OH⁻] = 3.55×10⁻¹⁰M