A steel tank with a volume of 2.15 L contains N2 gas under a pressure of 8.91 atm at 5.81°C. Calculate the number of moles of N2 in the tank.

The answer to your question is   n = 0.838 moles

Explanation:

Data

Volume = 2.15 l

Pressure = 8.91 atm

Temperature = 5.81°C

moles = ?

Gas constant = 0.082 atm l / mol°K

Process

1.- Convert temperature to °K

Temperature = 5.81 + 273 = 278.81°K

2.- Write the Ideal gas formula

              PV = nRT

-Solve for moles (n)

              n = PV / RT

3.- Substitution

              n = (8.91 x 2.15) / (0.082 x 278.81)

4.- Simplification

               n = 19.16 / 22.86

5.- Result

               n = 0.838 moles

1. they vary with a higher number because boiling is way hotter than melting

po-215 i got it right on the quiz