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How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

The answer to your question is 37.5 l of water vapor

Explanation:

Data

volume of ethane = 12.5 l

volume of water vapor = ?

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒   4CO₂  +  6H₂O

-Convert the volume of C₂H₂ to moles

                    1 mol of C₂H₂ 22.4 l

                    x                     12.5 l

                             x = (12.5 x 1) / 22.4

                             x = 0.56 moles

-Calculate the moles of water vapor

                 2 moles of C₂H₂ 6 moles of H₂O

                 0.56 moles of C₂H₂  x

                          x = (0.56 x 6) / 2

                          x = 1.67 moles of H₂O

-Calculate the volume of water vapor

                          22.4 l of H₂O 1 mol

                             x                   1.67 moles

                             x = (1.67 x 22.4) / 1

                             x = 37.5 l

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.