What volume would 20.0 moles of sulfur dioxide occupy at 75.3 °C with a pressure of 2.16 atm?

V = 264.89 L

Explanation:

Given data:

Number of moles of sulfur = 20.0 mol

Volume of sulfur = ?

Temperature = 75.3°C

Pressure = 2.16 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

75.3+273.15 = 348.45 K

V = nRT/P

V = 20.0 mol × 0.0821 atm.L/ mol.K × 348.45 K  / 2.16 atm

V = 572.15 L/ 2.16

V = 264.89 L

14 days is the half-life of phosphorus-32