What is the volume, in Liters, of 0.765 mol of carbon monoxide gas at STP?

The volume at STP of 0,765 moles of carbon monoxide gas is 17, 125 L.

Explanation:

We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are : 1 atm pressure and 273 K temperature. Solve for the formula, V (volume):

PV=nRT ---> V= (nRT)/P

V= (0,765 mol x0,082 l atm/ K mol x 273 K)/ 1 atm

V= 17, 12529 L

c is the answer because when something is left after something evaporates that shows the chemical change.

"the periodic table is arranged in order of atomic number."