What is the pressure of 0.500mol of gas at 12.2 L and 273K

P = 0.92 atm

Explanation:

Given data:

Pressure of gas = ?

Number of moles = 0.500 mol

Volume of gas = 12.2 L

Temperature of gas = 273 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

P = nRT/v

P = 0.500 mol × 0.0821 atm.L/ mol.K   ×273 K/ 12.2 L

P = 11.2 /12.2 L

P = 0.92 atm

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .