Calculating grams:

If you wanted to make 0.800 Liters of a 0.531 M solution of Nickel (II) chloride, NiCl2, how many grams of NiCl2 would you need?
M = 0.531 M
n = 0.4248 mol
V = 0.800 L

n = M x V 0.4248 = 0.531 x 0.800

Now that you know the number of moles, you will need the molar mass of NiCl2 to calculate the grams of NiCl2.

Ni = 58.6934 = 59
Cl = 35.453 x 2 = 35 x 2 = 70
NiCl2 = 129 g/mol

Now use the unit canceling method to determine the grams of NiCl2 required:

.4248 mol NiCl2 x 129 g NiCl2 / 1 mol NiCl2 = 54.799 g NiCl2

Is this correct??

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