Part 1 involved MeOH addition to form the key tetrahedral intermediate. Part 2 involves loss of H2O from the tetrahedral intermediate to form the ester. Part 2 of 2: Intermediate species (from Part 1):

For all remaining steps in the mechanism: 1) Draw each species (organic and inorganic) resulting from the previous step. Each step will include all of, and only, the atoms given in the first step (i. e., do not use extra reagent molecules/ions, and do not omit spectator ions).

(Depending on how you drew the mechanism, the drawing area below might not be needed. Do not draw the final products.)

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.