Rank the following solutions from the highest [H3O+] (1) to the lowest [H3O+] (5).

[H3O+] = 3.16 × 10–4 M
[OH–] = 4.35 × 10–2 M
pH = 1.05
pOH = 7.0
pOH = 4.0

2,5,1,3,4

Explanation:

i did it

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally