A volume of gas occupies 1.2 L at 5.1 kPa. What volume would the gas occupy at 2.2 kPa?

2.78 L

Explanation:

Given that,

Original volume V1 = 1.2 L

Original pressure P1 = 5.1 kPa

New pressure P2 = 2.2 kPa

New volume V2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

5.1 kPa x 1.2L = 2.2 kPa x V2

6.12 kPa L = 2.2 kPa x V2

V2 = 6.12 kPa L / 2.2L

V2 = 2.78 L

Thus, the new volume of the gas would be 2.78 Liters

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

you need to have a picture of the atom that way we can answer it