Regarding the lyman series of hydrogen, calculate the frequency of the n = 5 line.

The Lyman series can be expressed in the formula 1/λ=RH(1−1/n2) where RH=1.0968×107m−1=13.6eVhc

Where n is a natural number greater than or equal to 2 (i.e. n = 2,3,4,...). Therefore, the lines seen in the image above are the wavelengths corresponding to n=2 on the right, to n=∞on the left (there are infinitely many spectral lines, but they become very dense as they approach to n=∞ (Lyman limit), so only some of the first lines and the last one appear).
 The wavelengths (nm) in the Lyman series are all ultraviolet
:23 45 6 7 8 9 10 11
 Wavelength (nm)121.6102.697.39593.893.192.692.392.191.991.18 (Lyman limit)
In your case for the n=5 line you have to replace "n" in the above formula for 5 and you should get a value of 95 x 10^-9 m for the wavelength. then you have to use the other equation that convert wavelength to frequency.

Coal i believe hope this