How many moles of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 1.09 atm and a temperature of 298K?

There are 0,89 moles of nitrous oxide gas  in the balloon.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K

n= 0,89212637 mol

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence