50ml of 6.0M NaOH provides an excess of NaOH for the reaction. How many mLs of 6.0M NaOh are actually needed to react with 10.0g of triglyceride?

The volume of 6 M NaOH is 5.5 ml

Explanation:

The equation of reaction is

C₃H₅(C₁₇H₃₅COO)₃+3 NaOH → C₃H₅(OH)₃+3 C₁₇H₃₅COONa

The molar mass of triglyceride M is 890 g/mole, so in 10.0 g of its are

From the equation of reaction one mole of triglyceride reacts with three moles of NaOH.

So,

the quantity moles of NaOH which actually needed to react is:

0.011 x 3=0.033 moles.

These  quantity moles of NaOH are consist in      

∴The volume of 6 M NaOH is 5.5 ml

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-