How many moles of Fe2O3 will be produced from a 18.0 grams of Fe

The answer to your question is 0.113 moles of Fe₂O₃

Explanation:

Data

moles of Fe₂O₃ = ?

mass of Fe₂O₃ = 18 grams

Process

1.- Calculate the molar mass of Fe₂O₃

Fe₂O₃ = (56 x 2) + (16 x 3)

          = 112 + 48

          = 160 g

2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.

                   160 g of Fe₂O₃ 1 mol

                     18 g of Fe₂O₃ x

                            x = (18 x 1)/160

                           x = 0.113 moles of Fe₂O₃

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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