1. The combustion of ethene, C2H4, is an exothermic reaction. Use the information below to
determine the amount of energy given off when 2.3 moles of ethene is combusted.
C2H4 + 3 02 02 CO2 + H2O
AH= - 1390 kJ

-3197 kj

Explanation:

Chemical equation:

C₂H₄ + O₂   →   CO₂ + H₂O       ΔH = -1390 KJ

Balanced chemical equation:

C₂H₄ + 3O₂   →   2CO₂ + 2H₂O    ΔH = -1390 KJ

It can be seen in equation that one mole of C₂H₄ react with 3 mole of oxygen and produced 1390 kj energy.

When 2.3 moles C₂H₄ react the energy produced is,

1 mole =  -1390 KJ

2.3 mol × -1390 KJ/ 1mol = -3197 kj

The given reaction is combustion reaction of hydrocarbon. when hydrocarbons burn in the presence of oxygen carbon dioxide and water are produced.

In given reaction 1 mole of ethylene react with 3 moles of oxygen and produced 2 moles of CO₂  and 2 moles of water.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.