How much energy is absorbed with radiation of wavelength of 200 nm?

E = 0.09 × 10⁻¹⁷J

Explanation:

Given data:

wavelength of radiations = 200 nm (200× 10⁻⁹ m)

Energy absorbed = ?

Solution:

Formula:

E = hc/λ

h = 6.63× 10⁻³⁴ Js

c = 3 × 10⁸ m/s

Now we will put the values.

E = 6.63× 10⁻³⁴ Js × 3 × 10⁸ ms⁻¹  / 200× 10⁻⁹ m

E = 19.89 × 10⁻²⁶ J / 200× 10⁻⁹

E = 0.09 × 10⁻¹⁷J

- lead + phosphoric acid = hydrogen + lead(ii) phosphate