Given the reaction represented by the balanced equation:

CH4(g)+3F2(g)->3HF(g)+CHF3 calculate the number of g of CHF3 that could be produced by mixing 180 g F2 with excess CH4.

Explanation:

As given in the question that methane() is taken excess amount

mass of depend only on mass of fluorine

mass of =180 g

mole of = =9.47

3 mole of gives 1 mole of

so 1 mole will give mole of

therefore,

9.47 mole of will give mole of

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