C3H8+5O2 -> 3CO2+4H2O How many moles of CO2 will be produced from 97.0 g of C3H8, assuming O2 is available in excess?

6.63moles

Explanation:

Given parameters:

Mass of C₃H₈  = 97g

Unknown:

Number of moles of CO₂  = ?

Solution:

Let us write the balanced reaction equation;

           C₃H₈    +   5O₂        →      3CO₂      +     4H₂O

To solve this problem, we have to work from the known to the unknown. The known here is C₃H₈.

Since the problem suggested that O₂   is excess, C₃H₈ is the limiting reactant that will determine the amount of product formed.

First find the number of moles of C₃H₈;

       Number of moles of C₃H₈ =

                  Molar mass of  C₃H₈  = 3(12)  + 8(1) = 44g/mol

      Number of moles of  C₃H₈    =    = 2.21moles

From the balanced reaction equation;

     1 mole of  C₃H₈  will produce 3 moles of CO₂;

   2.21 moles of C₃H₈  produces (2.21 x 3)moles of CO₂   = 6.63moles

the objects have the same charge.