A 2.0 L sample of hydrogen expanded to a new volume of 5.5L whole its pressure decreased to a 0.5 atm what was the original pressure of the example

1.375 atm

Explanation:

Given that,

Original volume V1 = 2.0 L

original pressure P1 = ?

New volume V2 = 5.5L

New pressure P2 = 0.5 atm

Since pressure and volume are involved while temperature is constant, apply Boyle's law

P1V1 = P2V2

P1 x 2.0 L = 0.5 atm x 5.5L

P1 x 2.0 L = 2.75 atmL

P1 = 2.75 atmL / 2.0 L

P1 = 1.375 atm

Thus, the original pressure of the hydrogen gas is 1.375 atm