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Chemistry, 08.04.2020 05:30 dondre54

Iron metal reacts with hydrochloric acid as follows:
2Fe(s) + 6HCl(aq) + 2FeCl3(aq) + 3H2(g)
If 2.40 mol of iron react with excess HCI, and 2.00 mol of H2 are
collected, what is the percent yield of the reaction?
100%
55.6%
83.3%
120%
66.7%

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Answers: 1

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Iron metal reacts with hydrochloric acid as follows:
2Fe(s) + 6HCl(aq) + 2FeCl3(aq) + 3H2(g)
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