G Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 0.96 g of methane is mixed with 6.37 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

2.64 g of carbon dioxide that could be produced by the chemical reaction.

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of require = 2 moles of

Thus 0.06 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 1 moles of give = 1 mole of

Thus 0.06 moles of give =  of

Mass of

Thus 2.64 g of carbon dioxide that could be produced by the chemical reaction.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.