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Chemistry, 08.04.2020 03:16 cici65360

There is more redox chemistry in the workup. Excess iodine reacts with thiosulfate to form iodide and dithionate: I2 (aq) + 2 S2O3 2ā€“ (aq) ā†’ 2 Iā€“ (aq) + S4O6 2ā€“ (aq) What is the practical advantage of reducing excess iodine to iodide (i. e. how does this make it easier to collect pure product)?

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There is more redox chemistry in the workup. Excess iodine reacts with thiosulfate to form iodide an...
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