Citric acid, also known as vitamin C, is a triprotic acid with the formula H3C6H5O7. The pKa values are 3.13, 4.76, and 6.40. What will be the approximate pH of a solution of sodium monohydrogencitrate, Na2HC6H5O7?

pH = 5.58

Explanation:

Given that :

Citric acid  is a triprotic acid with the formula . Tripotic acids are acids that have the tendency to yield three protons per molecule during the phases of dissociation, therefore they have three pka.

For Citric acid; the pka values are:

So, the pH of sodiummonohydrogencitrate with the chemical formula which can act as an acid and a base (i.e it is said to be amphoteric) can be calculated as :

pH = 5.58

Therefore, the approximate pH of a solution of sodium monohydrogencitrate = 5.58

the answer is 0.42 is that is an option. this question provides no info