If 19.3 moles of heptane (C7H16) are reacted with an excess of oxygen gas, how many moles of carbon dioxide (CO2) should be produced? (Round to the tenths place)

1 C7H16 + 11 O2 -> 7 CO2 + 8 H2O

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  the volume of  0.220 m k2s    solution  required  to  completely  react with 175 ml  of 0.115m co(no3)2  calculate the moles  of co(no3)2 =  molarity x volume/1000175 x0.115/1000= 0.02  moleswrite  the reacting  equationk2s(aq)  +  co(no3)2  = 2 kno3(aq)  + cos(s)by  use  of mole ratio between k2s to co(no3)2 which  is  1: 1 the moles of k2s is therefore = 175  x0.115/1000= 0.02  molesvolume = moles/molarity=0.02/0.22=0.09  ml  of k2s